1/7x^2-3=4

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Solution for 1/7x^2-3=4 equation: 


x in (-oo:+oo)

(1/7)*x^2-3 = 4 // - 4

(1/7)*x^2-4-3 = 0

1/7*x^2 = 7 // : 1/7

x^2 = 49

x^2 = 49 // ^ 1/2

abs(x) = 7

x = 7 or x = -7

x in { 7, -7 }

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